Integrand size = 15, antiderivative size = 77 \[ \int \frac {1}{\left (a x^3+b x^6\right )^{5/3}} \, dx=\frac {1}{2 a x^2 \left (a x^3+b x^6\right )^{2/3}}-\frac {3 \sqrt [3]{a x^3+b x^6}}{4 a^2 x^5}+\frac {9 b \sqrt [3]{a x^3+b x^6}}{4 a^3 x^2} \]
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Time = 0.04 (sec) , antiderivative size = 77, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {2026, 2041, 2025} \[ \int \frac {1}{\left (a x^3+b x^6\right )^{5/3}} \, dx=\frac {9 b \sqrt [3]{a x^3+b x^6}}{4 a^3 x^2}-\frac {3 \sqrt [3]{a x^3+b x^6}}{4 a^2 x^5}+\frac {1}{2 a x^2 \left (a x^3+b x^6\right )^{2/3}} \]
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Rule 2025
Rule 2026
Rule 2041
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2 a x^2 \left (a x^3+b x^6\right )^{2/3}}+\frac {3 \int \frac {1}{x^3 \left (a x^3+b x^6\right )^{2/3}} \, dx}{a} \\ & = \frac {1}{2 a x^2 \left (a x^3+b x^6\right )^{2/3}}-\frac {3 \sqrt [3]{a x^3+b x^6}}{4 a^2 x^5}-\frac {(9 b) \int \frac {1}{\left (a x^3+b x^6\right )^{2/3}} \, dx}{4 a^2} \\ & = \frac {1}{2 a x^2 \left (a x^3+b x^6\right )^{2/3}}-\frac {3 \sqrt [3]{a x^3+b x^6}}{4 a^2 x^5}+\frac {9 b \sqrt [3]{a x^3+b x^6}}{4 a^3 x^2} \\ \end{align*}
Time = 0.26 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.60 \[ \int \frac {1}{\left (a x^3+b x^6\right )^{5/3}} \, dx=\frac {-a^2+6 a b x^3+9 b^2 x^6}{4 a^3 x^2 \left (x^3 \left (a+b x^3\right )\right )^{2/3}} \]
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Time = 0.58 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.53
method | result | size |
pseudoelliptic | \(-\frac {-9 b^{2} x^{6}-6 a b \,x^{3}+a^{2}}{4 x^{2} \left (x^{3} \left (b \,x^{3}+a \right )\right )^{\frac {2}{3}} a^{3}}\) | \(41\) |
gosper | \(-\frac {x \left (b \,x^{3}+a \right ) \left (-9 b^{2} x^{6}-6 a b \,x^{3}+a^{2}\right )}{4 a^{3} \left (b \,x^{6}+a \,x^{3}\right )^{\frac {5}{3}}}\) | \(46\) |
trager | \(-\frac {\left (-9 b^{2} x^{6}-6 a b \,x^{3}+a^{2}\right ) \left (b \,x^{6}+a \,x^{3}\right )^{\frac {1}{3}}}{4 \left (b \,x^{3}+a \right ) x^{5} a^{3}}\) | \(50\) |
risch | \(-\frac {\left (b \,x^{3}+a \right ) \left (-7 b \,x^{3}+a \right )}{4 a^{3} x^{2} \left (x^{3} \left (b \,x^{3}+a \right )\right )^{\frac {2}{3}}}+\frac {b^{2} x^{4}}{2 a^{3} \left (x^{3} \left (b \,x^{3}+a \right )\right )^{\frac {2}{3}}}\) | \(62\) |
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Time = 0.28 (sec) , antiderivative size = 54, normalized size of antiderivative = 0.70 \[ \int \frac {1}{\left (a x^3+b x^6\right )^{5/3}} \, dx=\frac {{\left (9 \, b^{2} x^{6} + 6 \, a b x^{3} - a^{2}\right )} {\left (b x^{6} + a x^{3}\right )}^{\frac {1}{3}}}{4 \, {\left (a^{3} b x^{8} + a^{4} x^{5}\right )}} \]
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\[ \int \frac {1}{\left (a x^3+b x^6\right )^{5/3}} \, dx=\int \frac {1}{\left (a x^{3} + b x^{6}\right )^{\frac {5}{3}}}\, dx \]
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none
Time = 0.21 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.49 \[ \int \frac {1}{\left (a x^3+b x^6\right )^{5/3}} \, dx=\frac {9 \, b^{2} x^{6} + 6 \, a b x^{3} - a^{2}}{4 \, {\left (b x^{3} + a\right )}^{\frac {2}{3}} a^{3} x^{4}} \]
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none
Time = 0.33 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.68 \[ \int \frac {1}{\left (a x^3+b x^6\right )^{5/3}} \, dx=\frac {b^{2}}{2 \, a^{3} {\left (b + \frac {a}{x^{3}}\right )}^{\frac {2}{3}}} - \frac {a^{9} {\left (b + \frac {a}{x^{3}}\right )}^{\frac {4}{3}} - 8 \, a^{9} {\left (b + \frac {a}{x^{3}}\right )}^{\frac {1}{3}} b}{4 \, a^{12}} \]
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Time = 8.28 (sec) , antiderivative size = 51, normalized size of antiderivative = 0.66 \[ \int \frac {1}{\left (a x^3+b x^6\right )^{5/3}} \, dx=\frac {{\left (b\,x^6+a\,x^3\right )}^{1/3}\,\left (-a^2+6\,a\,b\,x^3+9\,b^2\,x^6\right )}{4\,a^3\,x^5\,\left (b\,x^3+a\right )} \]
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